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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by MIGUEL VELECUA
MIGUEL VELECUA
1,090 Points

Hi there, please help me out

Please help me out, this code does not passes

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    string=string.lower()
    string=string.split(' ')
    resposta={}
    for items in string:
        if items not in resposta:
            resposta[items]=1

        else:
            resposta[items]+=1


    return resposta

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Did you notice the hint in the error message? "Be sure you're lowercasing the string and splitting on all whitespace!"

To split on "all whitespace" the argument to "split" should be left empty. Giving a space causes it to split only on individual spaces.