Hi,
Whats wrong with this code?
when i run it the outcome is [(3, 'c')] instead of [(1 'a'), (2, 'b'), (3, 'c')]

Question

def combo(mylist, mystring):
    myls = []
    for num, char in enumerate(mylist, mystring):
        combin = num,char
        mytuple = tuple(combin)        
        myls.append(mytuple)                   
        return myls

Steven Parker · Accepted Answer

The "enumerate" function takes one iterable argument, but this code is passing it two of them.  Perhaps you were intending to use something else?   See more details on the documentation page for enumerate() (https://docs.python.org/3/library/functions.html#enumerate).
Also, it's very difficult to read unformatted code.  When posting code in the forum, use the instructions for code formatting in the Markdown Cheatsheet pop-up below the "Add an Answer" area. :arrowheadingdown:
   Or watch this video on code formatting (https://teamtreehouse.com/library/code).

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Andrew Matimba

Andrew Matimba

Hi, Whats wrong with this code? when i run it the outcome is [(3, 'c')] instead of [(1 'a'), (2, 'b'), (3, 'c')]

1 Answer

Steven Parker

Steven Parker

Andrew Matimba

Andrew Matimba