Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial![](https://ecs-static.teamtreehouse.com/assets/views/marketing/shared/community-banner-white-47072046c51352fe6a69f5e691ff5700b28bb11d45197d7bdf066d9ea3f72d0c.webp)
![angel moreta](https://uploads.teamtreehouse.com/production/profile-photos/9825502/micro_tokyo.jpg)
angel moreta
2,912 PointsHint
Any way to get [(x,y),(x,y),(x,y).....] because I have no idea , but a good hint would help a lot.
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
def combo(x,y):
output = []
index = int()
for i in enumerate(y):
output.append(i)
return output
2 Answers
![Chris Freeman](https://uploads.teamtreehouse.com/production/profile-photos/1153532/micro_image.jpg)
Chris Freeman
Treehouse Moderator 68,425 PointsYou are very close!
- the
enumerate
function produces two items, a count and an item from the iterable. Thefor
loop should have two variables to receive them, such asfor index, item
- with these two items, you can construct a tuple by using the
index
to get an item from one iterable along with theitem
- the line
index = int()
is not needed
Post back if you need more help. Good luck!!!
![angel moreta](https://uploads.teamtreehouse.com/production/profile-photos/9825502/micro_tokyo.jpg)
angel moreta
2,912 PointsThank you ??