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Start your free trialMartin Wilter
iOS Development Techdegree Student 8,782 PointsHint: To check for an odd number you can use the remainder operator and 3
I wonder why the lesson suggest using n % 3 to check for odd numbers, doesn't it make more sense to use n % 2?
var results: [Int] = []
for n in 1...100 {
if n % 7 == 0 && n % 2 == 1 {
results.append(n)
}
}
Anjali Pasupathy
28,883 PointsAnjali Pasupathy
28,883 PointsYou're correct - using n % 2 would make more sense. It's probably a typo in the challenge.