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Python Python Basics (2015) Number Game App Even or Odd

Brian S.
Brian S.
3,176 Points
Posted by Brian S.
Brian S.
3,176 Points

Hmmm... any suggestions? Code is doing as I expect, still not getting answer correct.

i also tried altering the Else to: else num % > 0 : print('False') break

even.py 
def even_odd(num):
    while True:
        if num % 2 == 0:
            print('True')
            break
        else:
            print('False')
            break

2 Answers

zy93
.a{fill-rule:evenodd;}techdegree
zy93
Python Web Development Techdegree Student 6,879 Points

Hey there!

1) Remove the loop and "break" statements-- You don't need to check if a number is odd or even more than once

2) Don't print true or false, use return instead :D -- This is how you get the value out of the function for reuse, rather than just showing the answer on the screen.

Your use of the modulo function is spot on though!

Brian S.
Brian S.
3,176 Points
Brian S.
Brian S.
3,176 Points

wow, i was doing way too much. Thank you

Kristian Gausel
Kristian Gausel
14,661 Points
Kristian Gausel
Kristian Gausel
14,661 Points

I dont understand why you use a loop. Also it says you should return true or false, not print it. The code looks something like

def even_odd(num):
    return num % 2 == 0
Brian S.
Brian S.
3,176 Points
Brian S.
Brian S.
3,176 Points

I dont understand why i used a loop either, in hindsight. Thank you