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JavaScript JavaScript Loops Working with 'for' Loops The Refactor Challenge – Duplicate Code

Posted by Jason Swoboda
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Jason Swoboda
Full Stack JavaScript Techdegree Student 1,525 Points

How are you calling value() as a function inside randomRGB(value) if it's not a function?

Inside function randomRGB(value), you define the variable const color as a template literal that interpolates the argument value, but you add a () thus making it look like a function.

How does this work?

1 Answer

Steven Parker
Steven Parker
224,872 Points
Steven Parker
Steven Parker
224,872 Points

When randomRGB is called in the main program, the argument passed to it is randomValue, which is the name of a function. So for the duration of the randomRGB function, the parameter name "value" is equal to "randomValue", which means it can be called as a function.

When a function reference is passed as an argument to another function, this is often referred to as a "callback".