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Start your free trialHerman Brummer
6,414 PointsHow can I refactor this?
def combo(input1, input2):
counter = 0
new_list = []
for item in input1:
x = item, str(input2[counter])
new_list.append(x)
counter = counter + 1
return new_list
print (combo("abc", "def"))
I got this done after much work and faffing out, but yikes its long.
1 Answer
Chris Jones
Java Web Development Techdegree Graduate 23,933 PointsHey Herman,
I think your code looks good and isn't in need of much refactoring, but if you just want to know someone else's opinion - here's what I would change:
def combo(input1, input2):
counter = 0
new_list = []
for item in input1:
new_tuple = (item, input2[counter])
new_list.append(new_tuple)
counter += 1
return new_list
print (combo("abc", "def"))
The x
variable wasn't obviously a tuple to me (although I haven't done much python for a while), so renaming that variable to new_tuple
will help someone looking at your code understand it faster. Also, I enclosed the new_tuple
variable instantiation in parenthesis just because that seems to be the common practice after I googled it briefly. Next, you can increase the counter
variable using the shorthand operator += 1
instead of counter + 1
. Lastly, you don't need to use the str
function because you're passing a string already for the input2
parameter.
Overall though, I thought you did well :). Let me know if you have any more questions. Keep it up!