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Herman Brummer
6,414 PointsHow can I refactor this?
def combo(input1, input2):
counter = 0
new_list = []
for item in input1:
x = item, str(input2[counter])
new_list.append(x)
counter = counter + 1
return new_list
print (combo("abc", "def"))
I got this done after much work and faffing out, but yikes its long.
1 Answer
Chris Jones
Java Web Development Techdegree Graduate 23,921 PointsHey Herman,
I think your code looks good and isn't in need of much refactoring, but if you just want to know someone else's opinion - here's what I would change:
def combo(input1, input2):
counter = 0
new_list = []
for item in input1:
new_tuple = (item, input2[counter])
new_list.append(new_tuple)
counter += 1
return new_list
print (combo("abc", "def"))
The x variable wasn't obviously a tuple to me (although I haven't done much python for a while), so renaming that variable to new_tuple will help someone looking at your code understand it faster. Also, I enclosed the new_tuple variable instantiation in parenthesis just because that seems to be the common practice after I googled it briefly. Next, you can increase the counter variable using the shorthand operator += 1 instead of counter + 1. Lastly, you don't need to use the str function because you're passing a string already for the input2 parameter.
Overall though, I thought you did well :). Let me know if you have any more questions. Keep it up!