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iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

Posted by Miles Grofsorean
Miles Grofsorean
1,345 Points

How can I solve FizzBuzz with switch statements?

When I write out my cases, Xcode tells me "expression pattern of type 'Bool' cannot match values of type 'Int'". Why is this the case? I haven't declared any true/false constants, and I'm not sure how to declare what type (string, bool, int, etc) each case should produce (not sure that's even possible).

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {

    switch n {
    case n % 3 == 0: print("Fizz")
    case n % 5 == 0: print("Buzz")
    case n % 3 == 0 && n % 5 == 0: print("FizzBuzz")
    default: print ("\(n)")
    }

    return "\(n)"
}

3 Answers

David Papandrew
David Papandrew
8,386 Points
David Papandrew
David Papandrew
8,386 Points

Hey Miles, I don't know if this is the optimal way to do it, but this is how I passed this challenge:

func fizzBuzz(n: Int) -> String {
    switch (n%3, n%5) {
    case (0, 0): return "FizzBuzz"
    case (0, 1..<n): return "Fizz"
    case (1..<n, 0): return "Buzz"
    default: return "\(n)"
    }
}
Muratalin Appas
Muratalin Appas
1,725 Points
Muratalin Appas
Muratalin Appas
1,725 Points

You need to use "true" or "false" on switch statement and also you need to return something (like Strings: "Fizz", "Buzz") after each case.

func fizzBuzz(n: Int) -> String {
    // Enter your code between the two comment markers
    switch true {
    case n % 3 == 0 && n % 5 == 0: return "FizzBuzz"
    case n % 3 == 0: return  "Fizz"
    case n % 5 == 0: return "Buzz"
    default: print(n)
    }
    // End code
    return "\(n)"
}
Caleb Kleveter
MOD
Caleb Kleveter
Treehouse Moderator 37,862 Points
Caleb Kleveter
Caleb Kleveter
Treehouse Moderator 37,862 Points

The reason you get this is because when you have a statement with an equality operator ==, the statement returns true or false. That is the way programming languages work.