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![Dylan Basikoro](https://secure.gravatar.com/avatar/3277705c862531f5edca9873ac3ec4a9?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Dylan Basikoro
6,624 Pointshow can i solve this?
You've just learned about the next() and prev() methods. Use one of them to traverse from Wade Christensen to James McAvoy in the list of students.
how can i solve that?
<!DOCTYPE html>
<html lang="en">
<head>
<title>Document</title>
</head>
<body>
<h2>Student List</h2>
<ul class="student-list">
<li>James McAvoy</li>
<li>Alena Holligan</li>
<li>Wade Christensen</li>
<li>Matt Krzyzynski</li>
</ul>
<script src="jquery-3.2.1.min.js"></script>
<script src="app.js"></script>
</body>
</html>
$('li').eq(2).prev(2);
![Dylan Basikoro](https://secure.gravatar.com/avatar/3277705c862531f5edca9873ac3ec4a9?s=60&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Dylan Basikoro
6,624 PointsThank you very much
Jamison Habermann
11,691 PointsJamison Habermann
11,691 PointsThe .prev() method in jQuery does not accept any arguments. Instead, you chain an additional .prev().
$('li'').eq(2).prev().prev();