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Python Python Basics (2015) Shopping List App Continue

basil dhillo
PLUS
basil dhillo
Courses Plus Student 240 Points

how can i solve this ??

how can i solve this ??

breaks.py
def loopy(items):
    for item in items:
        if items[0] == "a":
            continue
        else:
            print(len[0:])
loopy(["abc","xyz"])
    # Code goes here

3 Answers

Stuart Wright
Stuart Wright
41,102 Points

There are two issues with your code. You need to check the first letter of 'item', not 'items', in your condition. This is because item refers to a single item in the list, but items is the entire list.

And in your else clause, you should simply print out the item, rather than what you are currently trying to print.

def loopy(items):
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(item)
basil dhillo
PLUS
basil dhillo
Courses Plus Student 240 Points

Thank you Sir, And Can You Please Suggest Me Any Other Way To Improve My Programming Skills..i-e Book or Tutorials anything

Stuart Wright
Stuart Wright
41,102 Points

You're welcome. I'm still learning myself, but I found the book Think Python to be a big help - available as a free eBook here:

http://greenteapress.com/wp/think-python-2e/