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basil dhillo
Courses Plus Student 240 Pointshow can i solve this ??
how can i solve this ??
def loopy(items):
for item in items:
if items[0] == "a":
continue
else:
print(len[0:])
loopy(["abc","xyz"])
# Code goes here
3 Answers
Stuart Wright
41,118 PointsThere are two issues with your code. You need to check the first letter of 'item', not 'items', in your condition. This is because item refers to a single item in the list, but items is the entire list.
And in your else clause, you should simply print out the item, rather than what you are currently trying to print.
def loopy(items):
for item in items:
if item[0] == "a":
continue
else:
print(item)
basil dhillo
Courses Plus Student 240 PointsThank you Sir, And Can You Please Suggest Me Any Other Way To Improve My Programming Skills..i-e Book or Tutorials anything
Stuart Wright
41,118 PointsYou're welcome. I'm still learning myself, but I found the book Think Python to be a big help - available as a free eBook here: