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JavaScript

Fernando Jimenez
PLUS
Fernando Jimenez
Courses Plus Student 8,455 Points

how come the .css() is not working? function not recognized?

so I first start by initializing var menu = jQuery('.hmenu_inner_holder')[0];

when I console.log menu it equals :

<div class="hmenu_inner_holder"> ...</div>

so its a bunch of html inside the <div class="hmenu_inner_holder"> div..

then I try to change the css by doing

menu.css("width":"68%"); but then I get this error:

// Uncaught SyntaxError: missing ) after argument list

I Also tried using a "," instead of ":"

then it said Uncaught TypeError: menu.css is not a function

Can you post the full code please, to get a better look at it?

1 Answer

Steven Parker
Steven Parker
230,248 Points

You were right that arguments should be separated by a comma, not a period. But when you applied the index to the jQuery function, it assigned "menu" with a plain HTML element instead of a jQuery object. And of course, plain elements don't have a ".css" method.

To select the first item as a jQuery object instead of a plain element, use the ".eq" method instead of the index:

var menu = jQuery('.hmenu_inner_holder').eq(0);