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JavaScript Practice forEach in JavaScript Practice forEach Challenge 5 Solution

Victor Stanciu
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Victor Stanciu
Full Stack JavaScript Techdegree Student 11,196 Points
Posted by Victor Stanciu
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Victor Stanciu
Full Stack JavaScript Techdegree Student 11,196 Points

How could this be written using the ternary operator?

I tried the code below, but I got an error saying (Bummer: Unexpected token continue):

const percentages = [34, 67, 12, 39, 90, 82, 22, 24, 99];
let upperRange = [];

// upperRange should be: [67, 90, 82, 99]
// Write your code below
percentages.forEach(percentage => (percentage > 50) ? (upperRange.push(percentage)));

2 Answers

Jason Larson
Jason Larson
8,353 Points

You're getting the error because you haven't given an alternate expression if the statement is false. Personally, I don't think it's beneficial to use a ternary here, as you're not doing anything with the false values, but that's not what you asked. Since you're not doing anything with the values if they are below 50, you can just do null . Try this:

percentages.forEach(percentage => (percentage > 50) ? (upperRange.push(percentage)) : null);

Alternatively, you could do this:

percentages.forEach(percentage => {if (percentage > 50) upperRange.push(percentage)});
Victor Stanciu
seal-mask
.a{fill-rule:evenodd;}techdegree
Victor Stanciu
Full Stack JavaScript Techdegree Student 11,196 Points
Victor Stanciu
.a{fill-rule:evenodd;}techdegree
Victor Stanciu
Full Stack JavaScript Techdegree Student 11,196 Points

Thank you, Jason Larson!

I tried using continue for the alternate expression if the statement is false, but looks like I forgot to update the code. I'd really appreciate if you could explain why continue doesn't work also.

Anyway, your answer solves my problem!

Jason Larson
Jason Larson
8,353 Points
Jason Larson
Jason Larson
8,353 Points

Honestly, I'm not 100% sure why continue doesn't work (and If I'm wrong, hopefully somebody will respond and give us the correct reason), but I suspect it has to do with the fact that continue is used for breaking out of a loop, and the way the forEach() method is structured, it's not processed in the same way as a standard loop. Since the method calls the function once for each element of the array, there's nowhere for the code to go if it continues. In my mind, I have to think of it more as a series of function calls rather than a loop, and it wouldn't make sense to try to use continue as a statement by itself in a function.

On the MDN Page for Array.prototype.forEach(), it says "Note: There is no way to stop or break a forEach() loop other than by throwing an exception. If you need such behavior, the forEach() method is the wrong tool."