How do I define Start to be falsey overtime?

A loop that runs with while True will never end because the value being checked by the while loop is True and not a condition. So to start, you will want to change your while loop to check by a condition that changes based on a value that is being mutated within the while loop. In this case start

while start > 0:

Here, we can now mutate the start variable's value to eventually make the start > 0 statement become false

Next you did not need to instantiate the start variable inside the while loop. You will want to keep that outside, otherwise you will be continually setting the value to 5 at the start of each loop iteration:

start = 5
while start > 0:

The predefined function even_odd also does not need to reside inside the while loop, so simply, move it out and leave it unmodified

Lastly, inside the loops, the challenge would like you to decrement the start value by one, so that the loop can check the value of start against 0

start -= 1

What you end up with is something like so

start - 5
while start > 0:
    random_num = random.randint(1,99)
    if even_odd(random_num):
        # Here is where the {} is even statement goes
    else:
        # Here is where the {} is odd statement goes
    start -= 1

Hi Joe,

I'm grateful for the time you've taken to help me in this exercise

I've finally understood the concept.

I've updated the codes but it says I got the "Print" all wrong.

Is there something wrong with the updated code?

import random 

start = 5

def even_odd(num):
    return not num % 2 
    # Since 0 is falsey, we have to invert it with not.

while start > 0 :
    random_num = random.randint(1,99)
    if even_odd(random_num) % 2 == 0:
        print("{} is even".format(random_num))
    else:
        print("{} is odd".format(random_num))

    start -= 1