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# how do i do a check to see if a number is a multiple of 7 and odd in a for in loop?

here is the code challenge: For this challenge, we'd like to know in a range of values from 1 to 100, how many numbers are both odd, and a multiple of 7.

To start us off, I've written a for loop to iterate over the desired range of values and named the local constant n. Your job is to write an if statement inside the for loop to carry out the desired checks.

If the number is indeed both an odd number and a multiple of 7, append the value to the results array provided.

Hint: To check for an odd number use the not operator to check for "not even"

logicalOperators.swift
```var results: [Int] = []

for n in 1...100 {
// Enter your code below
if results != 1 && results *= 7 {
}
// End code
}
```

It's with `n` that you have to check the condition not `results`. To check if the number are multiple of use the Remainder Operator `%`. This lets you know if a number is cleanly divisible if the results is `0`.

is multiple of 7

```6 % 7 == 0 // false
7 % 7 == 0 // true
8 % 7 == 0 // false
```

is odd (is not multiple of 2)

```1 % 2 != 0 // true
2 % 2 != 0 // false
3 % 2 != 0 // true
4 % 2 != 0 // false
```
```var results: [Int] = []

for n in 1...100 {
// Enter your code below

// if the remainer of n times 7 is equal to 0 (clean)
// and
// if the remainder of n times 2 is not equal to 0 (not clean)
if n % 7 == 0 && n % 2 != 0 {
// append it to the results array
results.append(n)
}
}

// results [7, 21, 35, 49, 63, 77, 91]
```

Keep on coding ? @du5rte