How do i do that, I am confused

Question

Write a function named members that takes two arguments, a dictionary and a list of keys. Return a count of how many of the items in the list are also keys in the dictionary.
```counts.py
You can check for dictionary membership using the
"key in dict" syntax from lists.
Example
my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
members(mydict, mylist) => 2
def members(dict1,list1):
```

Matthew Hill · Accepted Answer

Hi Dima, here's my solution. I think it's easier if you just loop through the items in the list and check for membership in the dictionary.
python
def members(dict1, list1):
    count = 0
    for key in list1:
        if key in dict1:
            count+=1
    return count

Let me know if that makes sense or not!
Matt

dima Dima · Answer

Thank you very much, it was far more simple then what I tried to do

dima Dima · Answer

I wrote this code but it still incorrect, what can I do?
count=0
index=0
def members(dict1,list1):
    for item in dict1:
        if item==list1[index]:
            count=count+1
            index=index+1
        else:
            index=index+1
            continue
    print(count)

Matthew Hill · Answer

It always helps to have another watch of the video, or maybe do a search online (sites such as stack overflow are usually very helpful), this way you can have some extra help figuring it out for yourself so you'll learn more than if I just gave you the answer.
As a hint try iterating through your list using:
 python
for item in list:
    # Do something here

Hope that helps!
Matt

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dima Dima

dima Dima

How do i do that, I am confused

4 Answers

Matthew Hill

Matthew Hill

Matthew Hill

Matthew Hill

dima Dima

dima Dima

dima Dima

dima Dima