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Jordan Man
2,736 PointsHow do i do this challenge? i am completely lost.
Lines are determined by last name, and they will end up in line 1 or line 2. Please help me fix the getLineFor method.
NEW INFO: chars can be compared using the > and < symbols. For instance 'B' > 'A' and 'R' < 'Z'
public class ConferenceRegistrationAssistant {
public int getLineFor(String lastName) {
/* If the last name is between A thru M send them to line 1
Otherwise send them to line 2 */
char line = lastName.charAt(0);
return line;
if (line >= m){
System.out.println("line 1");
} else {
System.out.println("Line 2");
}
}
}
2 Answers
jcorum
71,830 Points public int getLineFor(String lastName) {
/* If the last name is between A thru M send them to line 1
Otherwise send them to line 2 */
int line = 0; //initialize line
if (lastName.charAt(0) < 'M') { //get first letter and compare to 'M'
line = 1; //re-initialize line
} else {
line = 2;
}
return line;
}
}
Under the covers chars are ints (their values are their ASCII values) so they can be compared using comparison operators like <, >, etc.
jcorum
71,830 PointsThe int in public int getLineFor(...) is the return type, and what it's promising is that this function will return an int. In the if... else... statement you set line to either 1 or 2. And then, after the if... else... return line; returns the number to the calling program.
Jordan Man
2,736 Pointsperfect. thank you again!
Jordan Man
2,736 PointsJordan Man
2,736 Pointsbrilliant thank you for your help. and thank you for breaking it down so i would understand. i have just a follow up question about the final line "return line" what is that doing - with the introduction of the if statement isnt the only options to be put in either line 1 or line 2?