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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops Refactor Using a Loop

Jaime Rios
PLUS
Jaime Rios
Courses Plus Student 21,100 Points

How do I fix this?

It is supposed to log 12 numbers but it logs 11. I tried to change i<=24 but it says that it is not the solution.

script.js
for (i =2; i < 24; i +=2){ 
console.log();
}
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

3 Answers

Benjamin Payne
Benjamin Payne
8,142 Points

Hey Man, You are just missing the i in the console.log() function.

for (i = 2; i < 24; i +=2 ){ 
    console.log( i );
}
Jon Kussmann
PLUS
Jon Kussmann
Courses Plus Student 7,254 Points

Hi Jaime,

You were correct in that your for loop should go to i <= 24.

When you wrote the console.log statement in the code block, you forgot to tell it what you print. In this case you want to print the value of "i" like so:

console.log(i);
Caleb Kleveter
MOD
Caleb Kleveter
Treehouse Moderator 37,862 Points

Is there a less-then or equal-to operator that you can use?