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Chris Martinez
11,715 Pointshow do i separate the variables?
my understanding is that each variable needs to be separated by a comma when listing in this manner, but i can't seem to work a comma into my set without getting "parse error".
i've tried
three = a + b,
and
three = (a+b), but neither are passing. the only method that passes is
simply
three = a + b
without a comma.
and i can pass the subsequent variable tasks without the comma as well. how does the computer know they are separate variables?
1 Answer
James Anwyl
Full Stack JavaScript Techdegree Graduate 49,960 PointsFor this challenge you can just write each variable on its own line with a semi-colon at the end. No need to chain them together. For example:
var three = a + b;
var one = a;
var two = b;
To make a list of variables you just separate each one with a comma as per the example in the code challenge:
var a = 1,
b = 2,
c = 4;
Hope this helps! :)
Brent Cralley
18,541 PointsBrent Cralley
18,541 PointsChris,
I just went back and found the lesson that I believe you're asking about....
In this situation, you aren't listing out your variables in a way that you would need them separated with a comma. You're adding(concatenating) the values of the variables to create a new value for the variable "three".
Still confused? Yeah, it's hard to explain..... But I'll try my best.
In the example:
var a =1, b = 2, c = 4;
You're declaring 3 different variables, and that's why you need each one separated with a comma. If there were no commas, the computer would think "Ok, this guy wants one variable that says 'a = 1 b = 2 c = 4'" The commas tell the browser that that is the end of the variable, and that now it wants to create a new one following the comma.
After you've declared the variables as listed in the example, you can call them out in your code. If you're using an operator(+) in between the variables, it tells the browser that you want to add the values together(if they're both numbers). There is no need for a comma if you're using operators to do math or concatenate strings. In fact, it will normally cause an error, as you've found.
I hope this helps. If you're still confused, let me know what you're confused about, and I'll try my best to clarify.
-Brent