How do I set an "odd value" for this challenge?

Question

Here are the instructions for this code challenge:
For this challenge, we'd like to know in a range of values from 1 to 100, how many numbers are both odd, and a multiple of 7.
To start us off, I've written a for loop to iterate over the desired range of values and named the local constant n. Your job is to write an if statement inside the for loop to carry out the desired checks.
If the number is indeed both an odd number and a multiple of 7, append the value to the results array provided.
Hint: To check for an odd number use the not operator to check for "not even"
My question:
-How does the "If Statement" know an odd value or a multiple of 7?  
-Do I have to create a new variable?
```logicalOperators.swift
var results: [Int] = []
for n in 1...100 {
    // Enter your code below
// End code 
}
```

Jennifer Nordell · Accepted Answer

Hi there!  Remember the modulus operator?  It returns the remainder after a division.  5 % 2 will return a 1.  Because 2 goes into 5 twice with a remainder of 1.  So let's take a look at 36 % 6.  This will return a 0 because 36 divided by 6 is equal to 6 with a remainder of 0.  A number is said to be "evenly" divisible if it has no remainder (or remainder equal to 0).  We can tell if a number is even or odd by doing a modulus of 2.  
5 % 2 is 1.  
6 % 2 is 0.  
7 % 2 is 1.  
See a pattern here?
I think maybe you can get it with these hints, but let us know if you need more information :sparkles:

scottrussell · Answer

It would be a condition of the if statement and n is already the variable you will be using. 
If i%2 != 0 
It's an odd number 
And it's the same way way for 7.
And then if both are true you would append that to your result array.

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Lana Wong

Lana Wong

How do I set an "odd value" for this challenge?

2 Answers

Jennifer Nordell

Jennifer Nordell

scottrussell

scottrussell