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Paul Je
4,435 PointsHow Do You Declare Different Types to conform a struct into a Protocol?
Unsure of the syntax I'd need to declare them when I'd need to declare the overall type of the struct as both an Int and a String; the example prior only spoke of one where it would be a string. Therefore I don't know how to structure the return statement to include two different types of return values, any help would be appreciated!
protocol UserType {
var name: String { get }
var age: Int { get set }
}
struct Person: UserType {
let name: String
let age: Int
var DatGuyOrGirl: UserType {
return "\(name) \(age)"
}
}
let somePerson = Person(name: "Paul Je", age: 22)
2 Answers
Reed Carson
8,306 Pointsno bug, this worked for me
struct Person: UserType {
var name: String
var age: Int
}
let somePerson = Person(name: "Reed", age: 28)
its probably because you threw in that extra var there. It didnt ask for that
Tyler Andal
8,383 PointsI think there is a bug in this exercise.
Example:
protocol UserType { var name: String { get } var age: Int { get set } }
struct Person { var name: String var age: Int }
let somePerson = Person(name: "Tyler" age: 100)
Above I expect the following error: swift_lint.swift:13:39: error: expected ',' separator let somePerson = Person(name: "Tyler" age: 100)
Make modification protocol UserType { var name: String { get } var age: Int { get set } }
struct Person { var name: String var age: Int }
let somePerson = Person(name: "Tyler" , age: 100)
When I click Preview I no longer show errors in the output.html file
Next I click on Recheck work and I receive the following error below the challenge description: Bummer! Make sure that Person conforms to the UserType protocol