How do you do this?

Question

please help

teachers.py

# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.

dict = {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
        'Kenneth Love': ['Python Basics', 'Python Collections']}

def num_teachers(dict):
    num_teachers = 0
    for x in dict.keys():
        num_teachers += 1
    return num_teachers

def num_courses(dict):
    courses = 0
    for x in dict.values():
        for y in x:
            courses += 1
    return courses

def courses(dict):
    list = []
    for x in dict.values():
        for y in x:
            list.append(y)
    return list

def most_courses(dict):
    high = 0
    for teacher in dict:
        if len(dict[teacher]) > high:
            boss = []
            boss.append(teacher)
    return "".join(boss)


def stats(dict)
    total = []
    for x in dict:
        total.append([x])

Answer 1 · 2018-08-11T05:09:18Z

August 11, 2018 5:09am

I would do it as follows. Not clear what you wish to do for the stats part, but I'm assuming you can build that easily with the rest of the functions. Also: dict is a reserved word so don't use that as a variable name.

def num_teachers(d):
    return len(d)

def num_courses(d):
    return len(courses(d))

def courses(d):
    return [i for _, item in d.items() for i in item]

def most_courses(d):
    highest = max(len(d[x]) for x in d.keys())
    boss = [k for k,v in d.items() if len(v) == highest]
    return ",".join(boss)

Here's the output for your example:

>>> dictionary
{'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'], 'Kenneth Love': ['Python Basics', 'Python Collections']}
>>> num_teachers(dictionary)
2
>>> num_courses(dictionary)
4
>>> courses(dictionary)
['jQuery Basics', 'Node.js Basics', 'Python Basics', 'Python Collections']
>>> most_courses(dictionary)
'Andrew Chalkley,Kenneth Love'
>>> dictionary['Kenneth Love'].append('Django Fantastico')
>>> most_courses(dictionary)
'Kenneth Love'

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Emil Hejlesen

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How do you do this?

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Sumit Chawla

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