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Nicholas Wallen
12,278 PointsHow does it differentiate between the two different i counters?
for (let i=0; i< myRandomList.length; i++) { console.log('Item ' + i + ' in the array is ' + myRandomList[i] ); }
By using myRandomList[i], does that tell the compiler to look at the actual item in that place, versus just the index value?
1 Answer
Eric Queen
13,214 PointsThe 'i' variable is of type integer. To go directly to your question, it is not differentiating between the two different i counters because they are not different. You only have one i counter, which is the variable declared in the for loop.
The first i in you console.log statement is directly referencing the value of i, which in the first pass through the loop is 0. When referencing i the second time in your console.log statement you are using the value of i to find the value in the array for that index.
Using i by itself will give you the value of i. Using it in the place of the array index value will return the value at that index in the array.
Hope this helps!
Vahe Gharagiozyan
10,088 Pointsyea that cleared it up for me, thanks a lot!
Alexander Mackenzie
10,542 PointsAlexander Mackenzie
10,542 PointsIf you access an array value in a loop then it is going to access the index multiple times.
So i = 0 .... // display arr[0]
i = 1 ... // display arr[1]
etc.
So it doesn't differentiate between them. They are the same value but the value will change with each loop and this is how you can loop through and display an array's contents (for example).