How does my if else statement know whether my function is true or false.

Question

So basically I have the code below

class Tower {
    let position: Point
    var range: Int = 1
    var strength: Int = 1

    init(x: Int, y: Int) {
    self.position = Point(x: x, y: y)
    }

    func fireAtEnemy(enemy: Enemy) {
        if inRange(self.position, range: self.range, target: enemy.position) {
            while enemy.life > 0 {
                enemy.decreaseHealth(self.strength)
                print("The enemy has been vanquished!")
            }
        } else {
            print("Darn. The enemy is out of range!")
        }
    }

    func inRange(position: Point, range: Int, target: Point) -> Bool {
        let availablePositions = position.surroundingPoints(withRange: range)
        for point in availablePositions {
            if (point.x) == (target.x) && (point.y) == (target.y) {
                return true
            }
        }
        return false
    }
}

I understand most of it but I am stuck on one part and that is the inRange method called in the fireAtEnemy method.

There is an if else statement inside the fireAtEnemy method. Here, Pasan said that since inRange was true, it would run the code below. What if inRange was false? How does it know not to run enemy.decreaseHealth(self.strength) when it is false? Is it a basic concept I have missed? Does the if in an if else statement only run true statements while the else runs the false ones?

Answer 1 · 2016-03-17T05:54:38Z

March 17, 2016 5:54am

Nevermind, I figured it out... If statements only run if its true while else runs the false ones.

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Min Choi

Min Choi

How does my if else statement know whether my function is true or false.

1 Answer

Min Choi

Min Choi