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JavaScript

Posted by Nathan Ayala
Nathan Ayala
5,246 Points

how does the number in getRandomNumber(###); work? Why is it multiplying it by the number?

Im use to doing this the first way it is written, im not entirely sure how the getRandomNumber(6); is the same thing? When you place an integer into the parenthesis is it automatically multiplied and why?

function getRandomNumber( upper ) { var randomNumber = Math.floor( Math.random() * 6 ) + 1; return randomNumber; }

console.log(getRandomNumber());

function getRandomNumber( upper ) { var randomNumber = Math.floor( Math.random() * upper ) + 1; return randomNumber; }

console.log(getRandomNumber(6));

2 Answers

Piotr Manczak
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.a{fill-rule:evenodd;}techdegree seal-36
Piotr Manczak
Front End Web Development Techdegree Graduate 25,171 Points
Piotr Manczak
.a{fill-rule:evenodd;}techdegree seal-36
Piotr Manczak
Front End Web Development Techdegree Graduate 25,171 Points

It is some sort of witchcraft if you ask me.

Nathan Ayala
Nathan Ayala
5,246 Points

currently searching the bible for the answer

Piotr Manczak
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Piotr Manczak
Front End Web Development Techdegree Graduate 25,171 Points
Piotr Manczak
.a{fill-rule:evenodd;}techdegree seal-36
Piotr Manczak
Front End Web Development Techdegree Graduate 25,171 Points

Don't look in the bible. Try documentation on https://developer.mozilla.org/en-US/. All the answers are there. As a professional front-end developer you will be spending approx 80% looking through the documentation so you can get use to right now.