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### Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today. # how i can use // or int()?

I need you to create a new function for me. This one will be named sillycase and it'll take a single string as an argument. sillycase should return the same string but the first half should be lowercased and the second half should be uppercased. For example, with the string "Treehouse", sillycase would return "treeHOUSE". Don't worry about rounding your halves, but remember that indexes should be integers. You'll want to use the int() function or integer division, //.

sillycase.py
```def sillycase(i):
half = len(i) % 2
for x in i:
o = str(i[x]).lower()
i[x] = o

count = 0
count += 1
if count <= half:
break

for half in i:

o = str(i[x]).lower()
i[x] = o

return i
``` ## Here's an example:

If you were to divide 3 by 2 ("`3/2`"), the result would be 1.5, but that's not a valid value to use as an index. So if you enclosed the division in the int function ("`int(3/2)`") you would get a result of 1. You could also get that result by using the special integer division operator ("`3//2`"). I figured that. Well, let me suggest that you might rethink your strategy and you may find a simpler way to achieve the objective. And this simpler way might involve dividing a value by 2 and then using it as an index, but only if the result is an integer. I used len() and // to solve this question.

```def sillycase(n):
return n[0:len(n)//2].lower()+n[len(n)//2:].upper()
```