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Python Python Collections (2016, retired 2019) Slices sillyCase

ido sh
ido sh
3,926 Points
Posted by ido sh
ido sh
3,926 Points

how i can use // or int()?

I need you to create a new function for me. This one will be named sillycase and it'll take a single string as an argument. sillycase should return the same string but the first half should be lowercased and the second half should be uppercased. For example, with the string "Treehouse", sillycase would return "treeHOUSE". Don't worry about rounding your halves, but remember that indexes should be integers. You'll want to use the int() function or integer division, //.

sillycase.py 
def sillycase(i):
    half = len(i) % 2
    for x in i:
        o = str(i[x]).lower()
        i[x] = o

        count = 0
        count += 1
        if count <= half:
            break

    for half in i:

        o = str(i[x]).lower()
        i[x] = o

    return i

2 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Here's an example:

If you were to divide 3 by 2 ("3/2"), the result would be 1.5, but that's not a valid value to use as an index. So if you enclosed the division in the int function ("int(3/2)") you would get a result of 1. You could also get that result by using the special integer division operator ("3//2").

ido sh
ido sh
3,926 Points
ido sh
ido sh
3,926 Points

Thank you, but I mean to ask how I can use that function in the specific exercise

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

I figured that. :smile: Well, let me suggest that you might rethink your strategy and you may find a simpler way to achieve the objective. And this simpler way might involve dividing a value by 2 and then using it as an index, but only if the result is an integer.

Julie Maya
Julie Maya
14,666 Points
Julie Maya
Julie Maya
14,666 Points

I used len() and // to solve this question.

def sillycase(n):
    return n[0:len(n)//2].lower()+n[len(n)//2:].upper()