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iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

Benjamin Lim
Benjamin Lim
2,747 Points
Posted by Benjamin Lim
Benjamin Lim
2,747 Points

How is this even wrong. This is what i did first try. Checked the video and it was exactly the same?

really confused!

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
 for n in 1..100 {
  if (n % 3 == 0) && (n % 5 == 0) {
  return("fizzBuzz") 
  } else if (n % 3 == 0) {
  return("Fizz") 
 } else if (n % 5 == 0) {
 return("Buzz")
 } else {
 return(n) }
  return "\(n)"
} }

1 Answer

Jhoan Arango
Jhoan Arango
14,575 Points
Jhoan Arango
Jhoan Arango
14,575 Points

Hello Benjamin:

Reading the instructions is very important. The challenge says you don't need to do a loop, it also tells you not to worry about the else clause. You were very close to doing it, and you did the "logic" of it.

Here is a solution:

func fizzBuzz(n: Int) -> String {
    // Enter your code between the two comment markers
    if n % 3 == 0 && n % 5 == 0{
        return "FizzBuzz"
    } else if n % 3 == 0 {
        return "Fizz"
    } else if n % 5 == 0 {
        return "Buzz"
    }
    return "\(n)"
}

As you can see, it has the return it had already provided, and there is no loop nor else clause.

Good luck on your next challenge, and congratulations on this one.. This can be a difficult one to understand.

Benjamin Lim
Benjamin Lim
2,747 Points
Benjamin Lim
Benjamin Lim
2,747 Points

Hey Jhoan, i appreciate your help! I did notice him saying it in the video, but i tried it without a loop either and it didnt work. But yea, i see that it already provided with the return. Thanks so much!

Jhoan Arango
Jhoan Arango
14,575 Points
Jhoan Arango
Jhoan Arango
14,575 Points

Perhaps it was not passing because you also had "fizzBuzz" instead of "FizzBuzz".