Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Functions and Optionals Optionals Exercise: isDivisible function

Posted by Edgard Silva
Edgard Silva
2,711 Points

how is this not right?

I'm doing the last question of the optionals and we have to write a function thats opposite to the one before. so instead of checking if the numbers are divisible we'll check if they're not.

here's what i did....

func isNotDivisible (dividend: Int, divisor : Int) -> Bool { if dividend % divisor > 0 { return true } else { return false }

}

It gives me an error and i don't know why... PLEASE!! does anybody have an opinion. I only copied the second function and i am assuming we leave the first function (isDivisible()) in the code.

5 Answers

AVALONcomu Profile
AVALONcomu Profile
36,146 Points

It must be a function like this:

func isNotDivisible (#dividend: Int, #divisor: Int) -> Bool {
    if dividend % divisor != 0 {
        return true
    } else {
        return false
    }
Szymon Kadłuczka
Szymon Kadłuczka
8,762 Points
Szymon Kadłuczka
Szymon Kadłuczka
8,762 Points

First of all, the return type should be optional, so Bool? Secondly, if the statement is not true, return nil. Then you can use if-let.

Roger Martinez
Roger Martinez
3,239 Points
Roger Martinez
Roger Martinez
3,239 Points

What is the error you are seeing?

Nathan Smutz
Nathan Smutz
9,492 Points
Nathan Smutz
Nathan Smutz
9,492 Points

One issue I see is that you're testing for the remainder being greater than 0. It looks like the % operator can return a negative remainder (not the mathematical version of the mod function). So:

println(-9 % 4)

answers -1

So, your function might return a wrong answer if the remainder is less than 0.

Also, since the function you're reversing just returns true or false, you could reverse that with just:

return !isDivisible(dividend, divisor)
Edgard Silva
Edgard Silva
2,711 Points
Edgard Silva
Edgard Silva
2,711 Points

Actually the condition in the if statement was the wrong thing. i guess the " if dividend % divisor > 0" wasn't the way it was supposed to be. Thanks "Avalon community" i just changed the condition to " if dividend % divisor != 0" and now it worked! Thank you so much for the help guys