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How the method of the class beings passed aound?
Hi, The method within the class not in the constructor, So how it is passed around?
Steven Parker216,863 Points
Methods are peers of the constructor, they don't go inside it. But they are still part of the class, so they will exist in any instance of that class.
With respect to previous commenters, I think it's important to understand (as Ms. Boucher says) that
class is just syntactic sugar for prototypes.
Any object can access a property/method on one of its prototypes. Consider the following:
const greeting = "Hello"; greeting.toLowerCase(); // "hello"
It looks like the method
toLowerCase is being accessed on
greeting itself, but
greeting is just a string... In fact, it is a method of the prototype of the global
String object (hence MDN's docs reference to 'String.prototype.toLowerCase'), but
greeting can access it because a string automatically shares the same prototype as the
This is all that
class does in JS: when you 'instantiate' a class, you create an object and tell it to share the same prototype as the 'class' object, which contains the methods. Therefore you can call them on the 'instantiations' through prototypical inheritance. It is not 'passed around', it is 'borrowed' or 'accessed' from a prototype.
I hope this helps!