Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.Start your free trial
How the method of the class beings passed aound?
Hi, The method within the class not in the constructor, So how it is passed around?
With respect to previous commenters, I think it's important to understand (as Ms. Boucher says) that
class is just syntactic sugar for prototypes.
Any object can access a property/method on one of its prototypes. Consider the following:
const greeting = "Hello";
greeting.toLowerCase(); // "hello"
It looks like the method
toLowerCase is being accessed on
greeting itself, but
greeting is just a string... In fact, it is a method of the prototype of the global
String object (hence MDN's docs reference to 'String.prototype.toLowerCase'), but
greeting can access it because a string automatically shares the same prototype as the
This is all that
class does in JS: when you 'instantiate' a class, you create an object and tell it to share the same prototype as the 'class' object, which contains the methods. Therefore you can call them on the 'instantiations' through prototypical inheritance. It is not 'passed around', it is 'borrowed' or 'accessed' from a prototype.
I hope this helps!
Steven Parker229,018 Points
Methods are peers of the constructor, they don't go inside it. But they are still part of the class, so they will exist in any instance of that class.