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# How to check for logical checks in an IF statement

Hi I am trying to make the IF statement but I don't know how to check for logical Checks in an IF Statement?

Here is an example, where the operator "%" is used to determine the remainder (even numbers, when divided by 2, will have no remainder, and, therefore, the result of, say, "4 % 2" will be "0"):

```for x in 1...10 {
if x % 2 == 0 {
print("\(x) is even.")
} else {
print("\(x) is odd.")
}
}
```

The code that you have linked to in this also incorporates "&&" which allows you to add two conditionals in one place:

```if x > 5 && x < 10{

}
```

I don't want to give away the answer to the challenge TOO much, so let me know if this helps! :)

I know someone else had already received best answer, but it bothered me that the rest of my answer wasn't included my response, so I modified it so that it would.

PLUS

The challenge wants you to check for odd number && mutiple of 7.

Hint: To check for an odd number you can either use the remainder operator and 3, or use the not operator to check for "not even"

The hint says that you may use the not operator != to check for inequality.

One way to write the if statement is as the following

```if n % 2 != 0 && n % 7 == 0 {
// append number to the Array
}
```