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Java Spring Basics Modeling, Storing, and Presenting Data Create a POJO

How to Create a POJO? Also no preview button to view errors.

public class Contact { private int id; private String firstName; private String lastName; private String email;

public Contact(int id, String firstName, String lastName, String email) { this.id = id; this.firstName = firstName; this.lastName = lastName; this.email = email; }

public int getId() { return id; }

public int setId(id) { this.id = id; }

public String getFirstName() { return firstName; }

public String setFirstName(firstName) { this.firstName = firstName; }

public String getLastName() { return lastName; }

public String setLastName(lastName) { this.lastName = lastName; }

public String getEmail() { return email; }

public String setEmail(email) { this.email = email; } }

com/teamtreehouse/contactmgr/model/Contact.java
  public class Contact {
    private int id;
    private String firstName;
    private String lastName;
    private String email;

  public Contact(int id, String firstName, String lastName, String email) {
    this.id = id;
    this.firstName = firstName;
    this.lastName = lastName;
    this.email = email;
  }

  public int getId() {
    return id; 
  }

  public int setId(id) {
    this.id = id;
  }

  public String getFirstName() {
     return firstName;
  }

  public String setFirstName(firstName) {
    this.firstName = firstName;
  }

  public String getLastName() {
    return lastName;
  }

  public String setLastName(lastName) {
    this.lastName = lastName;
  }

  public String getEmail() {
    return email;
  }

  public String setEmail(email) {
    this.email = email;
  } 
}

1 Answer

Close. But you need a type for all your set methods, e.g., you have id for the parameter in setId, but you need int id

  public int setId(int id) {
    this.id = id;
  }

Also, for all your getters, the return type must be void as they return nothing:

  public void setId(int id) {
    this.id = id;
  }