How to get a if statement to look at two variables at once

Question

So I'm running the code 
isFizz= number%3
isBuzz= number%5
print("Hello", name)
print("So you picked",number,"lets see if thats a Buzz or Fizz or both!")
if isBuzz and isFizz ==0:
    print("thats a buzzfizz!")
elif is_Fizz <= 0:
          print("thats a fizz!")
elif is_Buzz <= 0:
          print("thats a buzz!")
else:
    print("thats not bizzy or fuzzy!")
and for some reason whenever I feed this the any number divisible by 3 it gives me a buzzfizz and if I  give it the number 15 it would give me a buzz. I don't understand what is going wrong here.

Scott Bailey · Answer

python
if is_Buzz == 0 and is_Fizz == 0:
    print("thats a buzzfizz!")

This would let you compare if both are True, you were close.
Another way that would work is:
python
if not is_Buzz and not is_Fizz:
    print("thats a buzzfizz!")

0 = Falsey
1 = Truthy
As the return on 15 % 5 = 0 and 15 % 3 = 0 both are read as False on the statement.
So the last example is saying if both are not False (ie True) then it will print.
I'm not sure which is better or even if one is better but both will work!
Full code:
```python
name = input("Enter Name: ")
number = input("Enter Number: ")
isFizz = (int(number) % 3)
isBuzz = (int(number) % 5)
print(f"Hello {name}")
print(f"So you picked {number} lets see if thats a Buzz or Fizz or both!")
if isBuzz == 0 and isFizz == 0:
    print("thats a buzzfizz!")
elif is_Fizz <= 0:
    print("thats a fizz!")
elif is_Buzz <= 0:
    print("thats a buzz!")
else: 
    print("thats not bizzy or fuzzy!")
```

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Sheila Hunter

Sheila Hunter

How to get a if statement to look at two variables at once

1 Answer

Scott Bailey

Scott Bailey