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How to list items in tuples as individual items in a list of different paired tuples

working on this exercise with a couple of days, am I over complicating whats being looked for? I've looked up online but couldn't find anything that helps. any help/direction would be very much appreciated

zippy.py
```# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo(first,second):
tlist = []
for x in tuple(first):
for y in tuple(second):
return tlist.append((x,y))
```

You don't want to return until you finish building the list.

Also, nested loops would generate too many items — you only want one item per list index, using both lists at the same time. So you could do something like this:

```def combo(first, second):
tlist = []
for x in range(0, len(first)):  # rely on both lists having the same length
tlist.append((first[x], second[x]))
return tlist
```

Or you could do it in one step using the zip function:

```def combo(first, second):
return list(zip(first, second))
```

could also use a list comprehension for one-liner

```def combo(x, y):
return [(x[i], y[i]) for i in range(0, len(x))]
```