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John Cuddihy
5,493 PointsHow to list items in tuples as individual items in a list of different paired tuples
working on this exercise with a couple of days, am I over complicating whats being looked for? I've looked up online but couldn't find anything that helps. any help/direction would be very much appreciated
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo(first,second):
tlist = []
for x in tuple(first):
for y in tuple(second):
return tlist.append((x,y))
2 Answers
Steven Parker
231,269 Points
You don't want to return until you finish building the list.
Also, nested loops would generate too many items — you only want one item per list index, using both lists at the same time. So you could do something like this:
def combo(first, second):
tlist = []
for x in range(0, len(first)): # rely on both lists having the same length
tlist.append((first[x], second[x]))
return tlist
Or you could do it in one step using the zip function:
def combo(first, second):
return list(zip(first, second))
Robin *
5,670 PointsRobin *
5,670 Pointscould also use a list comprehension for one-liner