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Dileep Pothula
540 PointsHow to Pack that to the dictonary
def word_count(string):
word = string.split()
for w in word:
length = len(w)
D = dict(**{w:length})
print(D)
word_count("I Want To Learn Python")
Output:
{'I': 1}
{'Want': 4}
{'To': 2}
Like this I want that in complete dictonary
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
def word_count(string):
word = string.split()
for w in word:
length = len(w)
D = dict(**{w:length})
print(D)
word_count("I Want To Learn Python")
[MOD: added ``` formatting -cf]
1 Answer
Chris Freeman
Treehouse Moderator 68,423 PointsYour approach is looking at the length of characters in each word. The challenge is looking to count how many times each word occurs in the string. Try for each word in the string:
- initialize an empty dictionary, like,
results = {} - if the word is not already in the dictionary,
if word not in results - then add the word to the dictionary with it's initial value 1,
results[word] = 1 - otherwise, increment the existing word's count by one
results[word] += 1 - remember to
returnthe results