How to pass method in a statement?

You need a foreach statement & member assignments:

<?php
include "helper.php";

$members = $results->fetchAll(PDO::FETCH_ASSOC);
foreach ($members as $member) {
  $member_id = $member[member_id];
  $email = $member[email];
  $fullname = $member[fullname];
  $level = $member[level];

  send_offer($member_id, $email, $fullname, $level);
}

Thank you for the input @cynthiaarnow.

She kinda went through all of that. In the video before the challenge, Alena shows that you need to do something like the $members = $results->fetchAll(PDO::FETCH_ASSOC); to fetch the results as an array.

The challenge explanation is saying that you need to loop though the results, which means that now you need a foreach loop. When you do foreach($members as $member), the $member will become the array fetched from the sql query. It will look kinda like this:

$member = [
    "member_id" => "info", 
    "email" => "info", 
    "fullname" => "info", 
    "level" => "info" 
]

The member_id, email, fullname and level are now keys and their info are the values. We need to get their values, so for that you do $member["member_id"], $member["email"], $member["fullname"], $member["level"].

Since we already have the function and know what the parameters are, we just need to give the the values needed.

  $member_id = $member["member_id"];
  $email = $member["email"];
  $fullname = $member["fullname"];
  $level = $member["level"];

And now we just call the function.

send_offer($member_id, $email, $fullname, $level);

So it becomes like Cindy showed.

<?php
include "helper.php";

$members = $results->fetchAll(PDO::FETCH_ASSOC);
foreach ($members as $member) {
  $member_id = $member["member_id"];
  $email = $member["email"];
  $fullname = $member["fullname"];
  $level = $member["level"];

  send_offer($member_id, $email, $fullname, $level);
}