How to return a function string

Question

I need help with the last challenge on swift functions and optionals. The challenge is: Modify the definition of the function named greeting to return a string and replace the println statement with a return statement. The function should return a greeting. For example, if you pass in a string "Tom" the the return string would be: "Hello Tom".

returns.swift

func greeting(person: String) -> String {
let person = "Tom"
return person

}
 println("Hello \(person)")

Answer 1 · 2015-07-24T21:55:51Z

July 24, 2015 9:55pm

You possible missed the purpose of the (person: String) part. This part makes it possible for you to call the function using greeting(), and then in between brackets use the 'person' part. This is why you don't need to declare 'person' within your function, as you declare it inside the brackets of greeting(), which becomes greeting("Tom")

Also, the function needs to return a greeting. At the moment, the only thing you return when your function 'greeting' is called, is 'person', which just is the name. Use the following to return the required string:

return "Hello \(person)"

This will result in your function ending up like this:

func greeting(person: String) -> String {
return "Hello \(person)"
}

The only thing to do from here on is to correctly call your function, which you do by the following:

greeting("Tom")

Note: The parameter person is specified when calling the function, so not inside the function itself!

Answer 2 · 2015-07-24T22:09:30Z

July 24, 2015 10:09pm

Awesome, thanks Rolf I understand way better now. I appreciate it!

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Paula Carvajal

Paula Carvajal

How to return a function string

2 Answers

Rolf Willems

Rolf Willems

Takudzwa Andy Tembani

Takudzwa Andy Tembani

Paula Carvajal

Paula Carvajal

Rolf Willems

Rolf Willems