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kaganulucay
Full Stack JavaScript Techdegree Student 16,491 PointsHow to scan String?
Question: Sample Input ---> 42, 3.1415,Welcome to Hackerrank Java tutorials!
Sample Output ----> String: Welcome to Hackerrank Java tutorials! Double: 3.1415 Int: 42
My codes are here:
import java.util.Scanner;
public class Solution {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int x=sc.nextInt();
double y=sc.nextDouble();
String s=sc.nextLine();
System.out.println("String: "+s);
System.out.println("Double: "+y);
System.out.println("Int: "+x);
}
}
I really don't understand what is wrong with this. That is really easy question but I am missing something. Could anyone help me about it?
2 Answers
Paolo Villanueva
7,654 PointsI have a hackerrank account and this is my work for this problem:
import java.util.Scanner;
public class Solution {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int x=sc.nextInt();
sc.nextLine();
double y=sc.nextDouble();
sc.nextLine();
String s=sc.nextLine();
//Complete this code
System.out.println("String: "+s);
System.out.println("Double: "+y);
System.out.println("Int: "+x);
}
}
The reason why you have to include sc.nextLine() after you read in an integer and double is to get rid of '\n'.
kaganulucay
Full Stack JavaScript Techdegree Student 16,491 Pointsis there any specific reason to do it like that? Paolo Villanueva
Paolo Villanueva
7,654 PointsIt's been so long since I've done Java myself but I will try to explain it.
nextInt() and nextDouble() only scans and gets the next int and double in the input buffer. It doesn't read in anything else. In this case, it doesn't read the new line character. If you want to read in the next line, you have to use nextLine()