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faisalrustom
1,300 PointsHow to solve this challenge?
Can someone please explain how to solve this challenge?
3 Answers
Nathan Tallack
22,159 PointsWhat you are going to want to do is have a for loop that runs over the dictionry and in that for loop use a switch to work out which category to append the dictionary value to.
In pseudocode, it would look something like this.
for key, value in dictionary {
switch key {
case "XXX", "YYY": list1.append(value)
case "AAA", "BBB": list2.append(value)
default: otherList.append(value)
}
}
Here we are using a "switch" to quickly do something that could otherwise be done in a much more time consuming if then else if type manner. :)
faisalrustom
1,300 PointsI tried this but it's not working
for (key, value) in world {
switch key {
case "BEL" : europeanCapitals.append(world[0]) }
}
Nathan Tallack
22,159 PointsClose. Try something like this.
for (key, value) in world {
switch key {
case "BEL", "LIE", "BER": europeanCapitals.append(value)
:)
faisalrustom
1,300 Pointsthanks it worked <3