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# how to solve this challenge? help, please...

please help. I don't understand what I need to do here.... also, can you remind me videos that will help me solve it, why do I need to use try: and except here? Thanks, Idan.

squared.py
```# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
if number == num:
return int(num) ** 2
elif string == num:
return string * len(string)
```

## You haven't defined any variables named "number" or "string".

I'm guessing you were trying to determine the type of the argument, but that's not a way to do it. But you don't need to anyway, that's the whole point of try and except. If you try to convert the argument into an integer within a try, it will either succeed (and then you can deal with the number) or go to the except where you can then deal with it as something else.

I'm sorry.... I still cannot solve it.... here is my code

```def squared(num):
try:
return int(num ** 2)
except ValueError:
return (num * len(num))
```

You are really close now!
But you can't square the input before you convert it to a number. So really your only issue now is that closing parenthesis is in the wrong place.

Thanks it worked, I will remember it for the future! it is possible with if statement though? if it is so how?

It wouldn't be easy to do this another way, because you can't assume the passed argument is an integer number to start with. It could just be a string. Your objective is to see if it can be converted to an integer.