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Python Technical Interview Prep: Python Basics Basic Python Let's Get Together

Allison Seim
Allison Seim
1,578 Points

how to split a string without a separator

how to match an alphabet of a string with the key of a dictionary

join.py
def morse_code(word):
    morse_dict = {
        'a': 'dot-dash',
        'b': 'dash-dot-dot-dot',
        'c': 'dash-dot-dash-dot',
        'd': 'dash-dot-dot',
        'e': 'dot',
        'f': 'dot-dot-dash-dot',
        'g': 'dash-dash-dot',
        'h': 'dot-dot-dot-dot',
        'i': 'dot-dot',
        'j': 'dot-dash-dash-dash',
        'k': 'dash-dot-dash',
        'l': 'dot-dash-dot-dot',
        'm': 'dash-dash',
        'n': 'dash-dot',
        'o': 'dash-dash-dash',
        'p': 'dot-dash-dash-dot',
        'q': 'dash-dash-dot-dash',
        'r': 'dot-dash-dot',
        's': 'dot-dot-dot',
        't': 'dash',
        'u': 'dot-dot-dash',
        'v': 'dot-dot-dot-dash', 
        'w': 'dot-dash-dash',
        'y': 'dash-dot-dash-dash',
        'z': 'dash-dash-dot-dot'
    }
    a = list(word)
    for i in a:
        if i == morse_dict.keys():
            return (morse_dict.values())
    # enter your code below

morse_code("govern")
Lening Li
Lening Li
689 Points

You can just do:

morse_dict.get(alphabet, '')

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 66,645 Points

Hey Allison Seim.

Strings can certainly be split, but not with an empty separator:

>>> "abcde".split('')
Traceback (most recent call last):
  File <stdin>, line 1, in <module>
ValueError: empty separator

The Pythonic way is to treat the string as a container, like a list. A str has an __iter__ method that will yield one character at a time.

So, you can do:

>>> list("abcde")
[a, b, c, d, e]
>>> for char in "abcde":
...     print(char)
... 
a
b
c
d
e

Your list(word) is perfect.

Since the whole alphabet is in morse_dict you don’t need the if, simply look up the character morse_dict[i]. The append this result to a list that can be later joined into a string. (Be sure to use a hyphen when joining)

Post back if you need more help. Good luck!!!