How to use.On()

Question

On line 6 of app.js, fix the code so when you add a color li dynamically, the click handler will still work.

I am not sure how to complete this task. I followed the code I wrote in the app.js when I watched the video, but it isn't working. Am I missing something or doing something wrong.

js/app.js

//Problem: No user interaction causes no change to application
//Solution: When user interacts cause changes appropriately
var color = $(".selected").css("background-color");

//When clicking on control list items
$(".controls").click, (function(){
  //Deselect sibling elements
  $(this).siblings().removeClass("selected");
  //Select clicked element
  $(this).addClass("selected");
  //cache current color
  color = $(this).css("background-color");
});

//When "New Color" is pressed
$("#revealColorSelect").click(function(){
  //Show color select or hide the color select
  changeColor();
  $("#colorSelect").toggle();
});

//update the new color span
function changeColor() {
  var r = $("#red").val();
  var g = $("#green").val();
  var b = $("#blue").val();
  $("#newColor").css("background-color", "rgb(" + r + "," + g +", " + b + ")");
}

//When color sliders change
$("input[type=range]").change(changeColor);

//When "Add Color" is pressed
$("#addNewColor").click(function(){
  //Append the color to the controls ul
  var $newColor = $("<li></li>");
  $newColor.css("background-color", $("#newColor").css("background-color"));
  $(".controls ul").append($newColor);
  //Select the new color
  $newColor.click();
});

//On mouse events on the canvas
  //Draw lines

index.html

<!DOCTYPE html>
<html>
<head>
    <title>Simple Drawing Application</title>
    <link rel="stylesheet" href="css/style.css" type="text/css" media="screen" title="no title" charset="utf-8">
</head>
<body>
    <canvas width="600" height="400"></canvas>
    <div class="controls">
        <ul>
            <li class="red selected"></li>
            <li class="blue"></li>
            <li class="yellow"></li>
        </ul>
        <button id="revealColorSelect">New Color</button>
        <div id="colorSelect">
            <span id="newColor"></span>
            <div class="sliders">
                <p>
                    <label for="red">Red</label>
                    <input id="red" name="red" type="range" min=0 max=255 value=0>
                </p>
                <p>
                    <label for="green">Green</label>
                    <input id="green" name="green" type="range" min=0 max=255 value=0>
                </p>
                <p>
                    <label for="blue">Blue</label>
                    <input id="blue" name="blue" type="range" min=0 max=255 value=0>
                </p>
            </div>
            <div>
            <button id="addNewColor">Add Color</button>
            </div>
        </div>
    </div>
    <script src="//code.jquery.com/jquery-1.11.0.min.js" type="text/javascript" charset="utf-8"></script>
    <script src="js/app.js" type="text/javascript" charset="utf-8"></script>    
</body>
</html>

Answer 1 · 2016-06-27T01:07:35Z

June 27, 2016 1:07am

Hi Jason,

Line 6 of the .js file as you correctly point out is incorrect. The challenge wants you to to use the jQuery on() method.

If we look at the second example in the documentation we can see:

$( "#dataTable tbody" ).on( "click", "tr", function() {
  console.log( $( this ).text() );
});

This gives us the format of what is expected for this method, if we apply it to our situation we end up with:

  $(".controls").on("click", "li", function(){...});

The full example is here:

//Problem: No user interaction causes no change to application
//Solution: When user interacts cause changes appropriately
var color = $(".selected").css("background-color");

//When clicking on control list item
  $(".controls").on("click", "li", function(){
  //Deselect sibling elements
  $(this).siblings().removeClass("selected");
  //Select clicked element
  $(this).addClass("selected");
  //cache current color
  color = $(this).css("background-color");
});

//When "New Color" is pressed
$("#revealColorSelect").click(function(){
  //Show color select or hide the color select
  changeColor();
  $("#colorSelect").toggle();
});

//update the new color span
function changeColor() {
  var r = $("#red").val();
  var g = $("#green").val();
  var b = $("#blue").val();
  $("#newColor").css("background-color", "rgb(" + r + "," + g +", " + b + ")");
}

//When color sliders change
$("input[type=range]").change(changeColor);

//When "Add Color" is pressed
$("#addNewColor").click(function(){
  //Append the color to the controls ul
  var $newColor = $("<li></li>");
  $newColor.css("background-color", $("#newColor").css("background-color"));
  $(".controls ul").append($newColor);
  //Select the new color
  $newColor.click();
});

//On mouse events on the canvas
  //Draw lines

Hope this helps.

KB

Answer 2 · 2016-06-27T01:04:00Z

June 27, 2016 1:04am

You can lookup jQuery's .on() documentation online.

Simply put:

$(<selector>).on(<event>, <handler>);

That's the simplest implementation. It does support other syntaxes that allow you to use delegation.

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Jason Peay

Jason Peay

How to use.On()

2 Answers

Kieran Black

Kieran Black

Aaron Martone

Aaron Martone