How would you print out in the console a shadow variable and a global variable from inside the function?

Hi Alberto,

It really comes down to how the first variable was scoped as generally if you want an external variable to be accessible on a global level you would pass it outside of any function that would impede it from been defined on the window object, take the following for example.

var a = 'Hello';

function b() {
    var a = 'World';
    console.log(window.a, a);
}

b();

This would work fine as the variable a has been defined on the window object since it's executing in a scope that isn't controlled by anything other than window itself, however take the following example.

;(function() {
    var a = 'Hello';

    function b() {
        var a = 'World';
        console.log(window.a, a); // undefined World
    }

    b();
})();

This would return undefined for window.a as the variable is no longer scoped to the window object which can be confusing, depending on the use cases you need this for it's much better to separate your code using a closure (i.e. the second example) which you won't have learned about yet but should after the beginners course as it helps to namespace your code away from 3rd party code which eliminates conflicts and allows for much easier access to global variables.