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Python

Posted by Dharmesh Nayee
Dharmesh Nayee
1,090 Points

I am a little confused about the code in the video...

I think i am getting confused with the order the lines of code are being run.

This code is before the split_check call got transfered into the try block.

(1) def split_check(total, number_of_people):
(2)   if number_of_people <= 1:
(3)        raise ValueError("more than 1 person is required to split the check")
(4) return math.ceil(total/number_of_people)

(5) try:
(6)   total_due = float(input("What is the total?   "))
(7)    number_of_people = int(input("How many people?   "))

(8) except ValueError:
(9)   print "oh no! Thats not a valid value.Try again...")

(10) else:
(11)   amount_due = split_check(total_due, number_of_people)
(12)   print("Each person owes ${}".format(amount_due))

this is how i think order of the code ran:

(5), (6) , (7), (10),

(11) - it calls the split_check function (2) - The if function catches the error as the number_of_people entered is less than or equal to1. (3) - it raises the value error ("more than 1 person is required to split the check"). END.

However after the split_check function got moved to the try block....

(1) def split_check(total, number_of_people):
(2)   if number_of_people <= 1:
(3)        raise ValueError("more than 1 person is required to split the check")
(4) return math.ceil(total/number_of_people)

(5) try:
(6)   total_due = float(input("What is the total?   "))
(7)    number_of_people = int(input("How many people?   "))
**(8)    amount_due = split_check(total_due, number_of_people)**

(9) except ValueError:
(10)   print "oh no! Thats not a valid value.Try again...")

(11) else:
(13)   print("Each person owes ${}".format(amount_due))

This is how i think the order of the code should have been run:

(5), (6), (7),(8), (2) the if function picks up the error (3) the value error "more than 1 person is required to split the check" is raised and displayed to the user.

my question is (based on the above order): 1) Why do we need to put the ValueError as err and then to print(err) when based on the above order of operation it should have printed that error message already? 2) How did line (10) run ? because this code would have been skipped.

I hope my question makes sense.