Challenge Task 4 of 5 Wow, I just can't stump you! OK, two more to go. I think this one's my favorite, though.

Create a function named most_courses that takes our good ol' teacher dictionary.

most_courses should return the name of the teacher with the most courses. You might need to hold onto some sort of max count variable.

The dictionary will look something like:

{'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],

'Kenneth Love': ['Python Basics', 'Python Collections']}

Each key will be a Teacher and the value will be a list of courses.

Your code goes below here.

def num_teachers(teachers): count = 0 for teacher in teachers: count += 1 return count

def num_courses(teachers): total = 0 for value in teachers.values(): for course in value: total += 1 return total

def courses(teachers): result = [] for courses in teachers.values(): result += courses return result

def most_courses(teachers): max_count = 0 professors = "" for teacher, num_course in teachers.items(): if len(num_courses) > max_count: max_count = len(num_courses) professors = teacher return professors

# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(teachers):
    count = 0
    for teacher in teachers:
        count += 1
    return count

def num_courses(teachers):
    total = 0
    for value in teachers.values():
        for course in value:
            total += 1
    return total

def courses(teachers):
    result = []
    for courses in teachers.values():
        result += courses
    return result

def most_courses(teachers):
    max_count = 0
    professors = ""
    for teacher, course_list in teachers.items():
        if len(course_list) > max_count:
            max_count = len(course_list)
            professors = teacher
    return professors