I am getting an error for my code.

Question

Here is my code for the shirts.php page.

<?php

$products = array();
$products[101] = array(
    "name" => "Logo Shirt, Red",
    "img" => "img/shirts/shirt-101.jpg",
    "price" => 18   
);
$products[102] = array(
    "name" => "Mike the Frog Shirt, Black",
    "img" => "img/shirts/shirt-102.jpg",
    "price" => 20
);
$products[103] = array(
    "name" => "Mike the Frog Shirt, Blue",
    "img" => "img/shirts/shirt-103.jpg",    
    "price" => 20
);
$products[104] = array(
    "name" => "Logo Shirt, Green",
    "img" => "img/shirts/shirt-104.jpg",    
    "price" => 18
);
$products[105] = array(
    "name" => "Mike the Frog Shirt, Yellow",
    "img" => "img/shirts/shirt-105.jpg",    
    "price" => 25
);
$products[106] = array(
    "name" => "Logo Shirt, Gray",
    "img" => "img/shirts/shirt-106.jpg",    
    "price" => 20
);
$products[107] = array(
    "name" => "Logo Shirt, Turquoise",
    "img" => "img/shirts/shirt-107.jpg",    
    "price" => 20
);
$products[108] = array(
    "name" => "Logo Shirt, Orange",
    "img" => "img/shirts/shirt-108.jpg",    
    "price" => 25,
);
?>
<?php 
$pageTitle = "Mike's Full Catelog of Shirts";
$section = "shirts";
include('inc/header.php'); ?>

    <div class="section page">

        <div class="wrapper">

          <h1>Mikes Full catelog of Shirts  </h1>

          <ul>
            <?php foreach($products as $product){ ?>
            <li><?php echo $product;?></li>
            <?php };?>
          </ul>
        </div>
    </div>

<?php include('inc/footer.php'); ?>

I am getting the error

 Notice: Array to string conversion in C:\xampp\htdocs\shirts.php on line 58
Array

Here is line 58

            <li><?php echo $product;?></li>

What am I doing wrong??

Answer 1 · 2014-10-08T23:53:17Z

October 8, 2014 11:53pm

Hi Jarrod,

Currently you are attempting to echo out an entire array which isn't possible as PHP doesn't have a to_string method like other languages do, instead you want to be echoing out the <key:value> pairs.

For example

<li><img src="<?php echo $product['img']; ?>" alt=""></li>

Answer 2 · 2014-10-09T10:49:43Z

October 9, 2014 10:49am

Hi Jarrod,

You can print your array like this, using key=>$value of $products array;

<ul> <?php foreach($products as $key=>$value){ ?> <li><?php echo $value['name'].'<br/>'; echo $value['img'].'<br/>'; echo $value['price']; ?> </li> <?php }; ?> </ul>

Answer 3 · 2015-01-08T01:44:30Z

January 8, 2015 1:44am

I am getting the same error. This is confusing because in the video at 2:21, Randy is supposedly using the same code, but he gets something else entirely.

I am using XAMPP on Windows 8. Randy is using MAMP. Perhaps this is a XAMPP vs MAMP issue, where the locals Apache servers are simply processing the PHP differently....

Answer 4 · 2015-03-08T17:46:05Z

March 8, 2015 5:46pm

You're getting a notice, which is a little like a warning, but it doesn't "break" the script. It just keeps plodding along, although there are server settings which allow you to either ignore them completely, or to generate notices like the one you're seeing so you're more aware of the problem.

Chances are really good in any real world application you wouldn't want to be echoing "Array" to the web page, so you get a notice, followed by the output:

Notice: Array to string conversion in /home/gavin/phptut/shirts.php on line 59

Array

That second line is the same echo'ed text you saw in the video, coupled by the Notice the server generated right before it. So it's "working" just like the video, you're just getting extra output to let you know that you probably didn't want to be doing that..

Chances are good on his development server, he has the flag turned off which generates those Notices.

Welcome to the Treehouse Community

Looking to learn something new?

jarrod Reeves

jarrod Reeves

I am getting an error for my code.

4 Answers

Chris Shaw

Chris Shaw

For example

justindelamerced

justindelamerced

Andrew Zhao

Andrew Zhao

Gavin Ralston

Gavin Ralston

Gary Calhoun

Gary Calhoun