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Start your free trialRachel Hutchings
4,293 PointsI am getting an error saying "I did not log the even numbers between 2 - 24" Though according to my code I should be?
The challenge is to log only the even numbers between 2 and 24. I am simplifying the code by placing it in a loop. This is what I have -
var evenNumber;
for (var i = 0; i < 24; i += 2) { console.log(evenNumber); }
I am either getting errors that it is logging 11 or 13 times instead of 12 (what it needs to be) or that it is not logging the even numbers between 2 and 24. No matter how much I tweak I can't get it to work. What am I missing? I tried making the var i = 2 and i <26 or i = 0 and i <= 24 but nothing seems to work! Help!
var evenNumber;
for (var i = 0; i < 24; i += 2) {
console.log(evenNumber);
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
Raphaël Seguin
Full Stack JavaScript Techdegree Graduate 29,228 PointsHi, there are two problems in your code. You need to change the value of your variable before you use it, and you should start at 2 and not 0. You can use this var in the for loop and then make it increment by two so you get only the even values, like this :
var evenNumber;
for (evenNumber = 2; evenNumber <= 24; evenNumber += 2) {
console.log(evenNumber);
}
I hope it helps.
Mike Henry
Courses Plus Student 5,373 PointsYou're close. You we're right to start the loop at i=2 and then you should end it at i<= 24 so it will include 24 and then just console.log the variable i or if you want to use the variable evenNumber you need to assign i to it (evenNumber = i) inside the loop. This is what I used: for (i=2;i<=24;i+=2){ console.log(i); }
Rachel Hutchings
4,293 PointsThanks, Mike! This was really helpful :)
Rachel Hutchings
4,293 PointsRachel Hutchings
4,293 PointsThanks so much! This solved it :) I had a feeling I was getting something mixed up with the vars. Thank you!