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Python

Posted by Odane Williams
Odane Williams
Courses Plus Student 6,634 Points

I am getting the try again error

I'm honestly stumped on this one. Is it my syntax?

morse.py 
class Letter:
    def __init__(self, pattern=None):
        self.pattern = pattern

    def __str__(self, pattern=None):
        self.pattern = pattern
        morse = []
        for item in pattern:
            if item == ".":
                morse.append("dot")
            elif item == "-":
                morse.append("dash")
        "-".join(morse)



class S(Letter):
    def __init__(self):
        pattern = ['.', '.', '.']
        super().__init__(pattern)

1 Answer

Steven Parker
Steven Parker
229,785 Points
Steven Parker
Steven Parker
229,785 Points

Here's a few hints:

  • the function should not require an argument, it should use the internal pattern
  • it should return "dash" for every "_" (underscore), but it currently looks for "-" (hyphen) instead
  • the final string still needs to be _return_ed
Odane Williams
Odane Williams
Courses Plus Student 6,634 Points

I revised it with a different way to loop through pattern and adjusted the code according top your hints. I'm still getting the same error. Syntax is what always gets me.

class Letter: def init(self, pattern=None): self.pattern = pattern

def __str__(self):
    pattern = self.pattern
    morse = []
    for item in range(len(pattern)):
        if item == ".":
            morse.append("dot")
        else item == "_":
            morse.append("dash")
    return "-".join(morse)

class S(Letter): def init(self): pattern = ['.', '.', '.'] super().init(pattern)

Steven Parker
Steven Parker
229,785 Points
Steven Parker
Steven Parker
229,785 Points

Converting the pattern into a range makes the "item"s numbers now that do not match in the tests.

Also, converting the "elif" into an "else" is creating a syntax error.

Both of those were OK in the original code.