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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

Zachary Ruffner
Zachary Ruffner
16,451 Points

I am getting this error "Bummer! I couldn't import `string_factory`." String_factory challenge.

Hey guys,

I am working the string_factory challenge and it works fine in workspaces but I keep getting the "I couldn't import 'string_factory'" error.

Here is my code:

template = "Hi, I'm {name} and I love to eat {food}! "

value = [ {"name" : "James", "food" : "peaches"}, {"name" : "Worf", "food" : "gaw"}, {"name" : "the gods", "food" : "ambrosia"},


def string_factroy(lst, string): new = [] for dict in lst: strint = string new.append(string.format(**dict)) return new

print(string_factroy(value, template))

Thanks for the help ahead of time,


# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
template = "Hi, I'm {name} and I love to eat {food}! "

value = [
    {"name" : "James", "food" : "peaches"},
    {"name" : "Worf", "food" : "gaw"},
    {"name" : "the gods", "food" : "ambrosia"},


def string_factroy(lst, string):
    new = []
    for di in lst:
        strint = string
    return new

print(string_factroy(value, template))

1 Answer

Ronit Mankad
Ronit Mankad
12,166 Points

Hi! This is easy to implement:

def string_factory(args):
    args_as_list = list(args) #Since args will be of type tuple, we convert to list
    ls = []
    for dic in args_as_list:
        st = template.format(name = dic['name'], food = dic['food'])
    return ls