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Python Introducing Lists Build an Application Multidimensional Musical Groups

Posted by David Juhan
David Juhan
637 Points

I am not able to solve this can anyone help me

please solve this

groups.py 
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
# Your code here
for everyone in musical_groups:
    everyone = ", ".join(musical_groups)

print(everyone)
Eldin Guzin
Eldin Guzin
6,010 Points
Eldin Guzin
Eldin Guzin
6,010 Points

you looped through the groups, but know you need to loop through each member of the group you just looped.You need to loop through everyone and then add the comma and space. Hope this helps !

2 Answers

nakalkucing
nakalkucing
12,964 Points
nakalkucing
nakalkucing
12,964 Points

Hi David! I ran your code in the challenge and found the following issues:

Firstly, your .join(musical_groups) returns an error.

Secondly, your print statement returns an error.

I'm tackling the second error first. The print statement must be a part of your for loop.

Now for the first issue, (This will be super confusing if I don't change the name of your variable. So I'm changing your variable to everyone2) your goal isn't to join everyone to musical_groups. Instead, each time you loop through musical groups you want to join everyone to everyone:

for everyone in musical_groups:
#      ^    Joining everyone...
    everyone2 = ", ".join(everyone)
#                           ^   ...to itself

Hope this helps! :) Let me know if that doesn't fix the errors and I'll try again.

David Juhan
David Juhan
637 Points
David Juhan
David Juhan
637 Points

Thank You, Guys. You Guys are awsome