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Nikki Turrisi
15,095 PointsI am struggling with this challenge question
I know my syntax is wrong, but I can't figure out why. I am stumped. Any help?
<!DOCTYPE html>
<html lang="en">
<head>
<title>JavaScript Foundations: Functions</title>
<style>
html {
background: #FAFAFA;
font-family: sans-serif;
}
</style>
</head>
<body>
<h1>JavaScript Foundations</h1>
<h2>Functions: Return Values</h2>
<script>
function arrayCounter (1, 2, 3);
return arrayCounter.length;
console.log(arrayCounter);
if(arrayCounter === 'undefined');
return 0;
console.log(arrayCounter);
</script>
</body>
</html>
5 Answers
Jesus Mendoza
23,274 PointsHi!
function arrayCounter (1, 2, 3) {
return arrayCounter.length;
}
console.log(arrayCounter);
if(arrayCounter === 'undefined') {
return 0;
}
console.log(arrayCounter);
You're using semi-colons instead of curly brackets
B Nawaz
13,402 PointsIndeed! Like Jesus said, you need to use curly braces for your function definition, as such:
function (param1, param2) { //outer curly braces //do some stuff
var curlyBracesUsed = true;
if (curlyBracesUsed) { //inner braces
return "Then everything works!";
} //inner braces
} //outer curly braces
If this helped, mark me right, I want some of those sweet sweet forum points! :D
Varuzhan Darbinyan
8,360 PointsThis should work ;)
function arrayCounter(array) {
if (typeof(array) === "string"){
return 0;
}
else if (typeof(array) === "number") {
return 0;
}
else if (typeof(array) === 'undefined') {
return 0;
}
else {
return array.length;
}
}
Edmund lok
Courses Plus Student 6,465 PointsHey maybe this will help!
<script> function arrayCounter (array) { if (typeof != 'object'){ return 0; } return array.length; } </script>
Edmund lok
Courses Plus Student 6,465 PointsHey maybe this will help!
<script> function arrayCounter (array) { if (typeof != 'object'){ return 0; } return array.length; } </script>