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Android Build a Simple Android App (2014) Basic Android Programming Using the Random Class

Posted by Siddhant Choyal
Siddhant Choyal
Courses Plus Student 644 Points

I am stuck on this question please help me!

I'm not able to find out my mistake, please help me.

RandomTest.java 
Random randomGenerator = new Random();
String intAsString;
intAsString randomNumber = ;
randomNumber = randomGenerator. nextInt(10);

1 Answer

Gunjeet Hattar
Gunjeet Hattar
14,483 Points

Hi Siddhant

Lets break it up as per challenge

Challenge 1
Initialize a new Random variable called randomGenerator using the Random() constructor. Hint: Don't forget to use the new keyword.

Which I believe you have already done

Random randomGenerator = new Random();

Challenge 2
Create a new int variable named randomNumber. Use the randomGenerator variable and its nextInt() method to get a random number. Do not set a range.

int randomNumber = randomGenerator.nextInt();

Challenge 3
Now limit the range of the randomNumber variable from 0 to 9. Use the version of nextInt() that has a parameter that specifies how many numbers to choose from

nextInt() function also takes a parameter there you can set the number of random variables it can generate

int randomNumber = randomGenerator.nextInt(10)

Why 10? Because n = n+1 ; if value is set to 9 through 0, it will always be an additional 1 in the range.

Challenge 4
Create a String variable named intAsString. Convert the randomNumber integer to a String value and store it in the intAsString variable. Hint: "Moosh" them together like in the video

If you would have had looked at the video, it takes about the Object type integer as opposed to primitive type int

String intAsString = Integer.toString(randomNumber);

Hope that helps.

Siddhant Choyal
Siddhant Choyal
Courses Plus Student 644 Points

Thanks soo much Gunjeet, you really helped me the most. Thanks a tone. Love u bro, u r awesome :)